This week's maths problem

Bewertung: 5 / 5

Stern aktivStern aktivStern aktivStern aktivStern aktiv
 

Problem of the week

exercice de maths de la semaine, math problem of the week, problema di matematica della settimana, सप्ताह के गणित समस्या, математическая задача недели, Ejercicio de matemáticas semanal, 今週の数学問題, בעיה מתמטית של השבוע, مشكلة الرياضيات الأسبوع, 这个周的数学问题, Haftanın matematik problemi, temporäre Problem vun der Woch, μαθηματικό πρόβλημα της εβδομάδας, math tatizo la wiki,

On Friday of each week we will post a new maths challenge.
You may submit your solution by the following Thursday.
Each problem contains two different levels of difficulty. You will be awarded from 2 to 12 points for a full answer.
Each series contains 12 problems before the stage winner is determined.
Your score will be published here.

In each series we will give away 3 books as prices. The prices will be drawn by lot among the best ten participants of the series. The books are kindly sponsored by Buchdienst Rattei of Chemnitz.

Suggestions for problems are welcome.

Deadline is 16th. May 2024.


German version - Italian version - French version - Spanish version  Hungarian Version Russian version  --> 中文/Chinese <-- --> Ελληνικά   <--

Series 66

problem 787

 

‘You always have to solve problems with right-angled triangles. But do you know when Pythagoras‘ birthday is?’ asked Grandad. ‘No idea,’ Bernd blurted out. ‘I admit the question is a bit mean, because this information hasn't been passed down. But the friends of Pythagoras know how to help themselves,’ grinned the grandad.
You use the information of a date. Day number d (1; ...; 31), month number m (1; ...; 12) and the year number j. This number can (does not have to) be a one-digit number, for example 2009 simply (if there are two zeros before the last digit) 9. The number can (does not have to) be a two-digit number, for example 2030 becomes 30 (if the second digit is a zero) or the year has four digits. If d², m² and j² can be put into the form a² + b² = c², then it is Pythagoras' birthday.
Examples: 5.12.2013 becomes 5² + 12² = 13² and 3.5.2004 becomes 3² + 4² = 5²
The numbers 2000 to 3000 can be used as years.
When was Pythagoras' birthday celebrated in the period up to 2010? 4 blue points
When is the next birthday celebrated and when is the last one in the period? 4 red points

Deadline for solution is the 16th. May.


 

 


-> Enigma <--

https://www.schulmodell.eu/images/stories/mathe/horst/raetsel.php

 

Send your solutions to Diese E-Mail-Adresse ist vor Spambots geschützt! Zur Anzeige muss JavaScript eingeschaltet sein!, if your answer contains attachments.

For text versions you can also use this form

--> here <--

Please give your full name so your points can be added to the score. If you would like to receive our weekly maths problem automatically you can

--> subscribe to our newsletter <-- .

Presently this newsletter is received by more than 2000 subscibers.

You can also send a paper copy of your solution as long as it is postmarked on or before the deadline.
adress:
Thomas Jahre
Paul-Jäkel-Straße 60
09113 Chemnitz
Germany


Links:

http://www.wurzel.org/

https://www.facebook.com/ArchimedesLab

http://people.missouristate.edu/lesreid/potw.html

post address:

Thomas Jahre
Chemnitzer Schulmodell
Stollberger Straße 25
09119 Chemnitz
Deutschland/Germany
QR-Code for this site
qrcodewochen

Kommentare   

0 #4 Jerry 2018-05-09 20:16
I'm gone to inform my little brother, that he should also go to
see this weblog on regular basis to obtain updated from
most up-to-date reports.
0 #3 unblocked games 2017-09-25 06:37
It is not my first time to pay a visit this web page, i am browsing this website dailly and
obtain good information from here every day.
0 #2 Quentin 2017-08-20 14:31
Hey Mike, got a question for you concerning my
goals.
+3 #1 Cora 2014-11-13 23:03
Hi therde to all, the contents existing at this site are truly remarkable for people knowledge, well, keep up the
nice woek fellows.

You have no rights to post comments.
Zum Kommentieren muss man angemeldet sein.